<?xml version="1.0"?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1 plus MathML 2.0//EN" "http://www.w3.org/Math/DTD/mathml2/xhtml-math11-f.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:m="http://www.w3.org/1998/Math/MathML">
<head>
   <meta name="viewport" content="width=device-width, initial-scale=0.6" />
<OBJECT ID="mathplayer" CLASSID="clsid:32F66A20-7614-11D4-BD11-00104BD3F987"> <!--comment required to prevent this becoming an empty tag--></OBJECT>
<?IMPORT NAMESPACE="m" IMPLEMENTATION="#mathplayer" ?>  <link rel="stylesheet" href="/css/matkonyv.css" />
  <script type="text/javascript" src="/scripts/matkonyv.js"></script> 
<!--
 <script type="text/javascript" src="http://cdn.mathjax.org/mathjax/latest/MathJax.js?config=MML_HTMLorMML" />
-->
<script src="https://polyfill.io/v3/polyfill.min.js?features=es6"></script>
<script id="MathJax-script" src="https://cdn.jsdelivr.net/npm/mathjax@3/es5/tex-mml-chtml.js"></script>


<meta name="GENERATOR" content="TtM 3.72" />
 <style type="text/css">
 div.p { margin-top: 7pt; }
 span.roman {font-family: serif; font-style: normal; font-weight: normal;} 
</style>
<title>Matkönyv feladatgyűjtemény: Algebra 9--10</title>
  <link rel="stylesheet" href="/mathdisplay.css" type="text/css" />
</head>
<body>
<div id="navigation">



<div class="navcenter">
<div class="navdiv">
<a href="index.html">&nbsp;Matkönyv megjelenítő főoldal&nbsp;</a>&nbsp;
|&nbsp;<a href="list_html.php?mode=sne---j-">&nbsp;Matkönyv feladatgyűjtemények listája&nbsp;</a>&nbsp;
|&nbsp;<a href="volume.php?mode=sne---j-&amp;volume=a_ii">&nbsp;Tartalomjegyzék&nbsp;</a></div>
</div></div><div align="center" class="tochead"><h1>5. FEJEZET: Vegyes feladatok</h1></div>
  <div id="mut" class="mut" onclick="style.display='none'; ">
    <div class="flec">Bezárás: <a class="flec" href="#">[ X ]</a> </div>
    <iframe type="application/xml" id="ifmut" width="80%" height="85%"></iframe>
  </div>

<div class="feladat"><b>Feladat: 5.1.</b><br /> <a name="RuboszamI02" />[<a href="bib_box.php?mode=sne---j-&amp;citation_num=108" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num=108'); return false;">108</a>] Oldjuk meg a következő egyenletet!

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mn>4</m:mn><m:mo>+</m:mo><m:mi>x</m:mi><m:mo>+</m:mo>

<m:mfrac><m:mrow><m:mn>1</m:mn></m:mrow>

<m:mrow><m:mn>9</m:mn></m:mrow>

</m:mfrac>

<m:mo>=</m:mo><m:mn>12</m:mn><m:mo>,</m:mo><m:mn>2</m:mn>

<m:msub><m:mrow><m:mi mathvariant="italic">y </m:mi></m:mrow><m:mrow><m:mn>3</m:mn></m:mrow>

</m:msub>

</m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

(Az egyenlet két oldalán ugyanaz a szám áll, a bal oldalon tízes,

a jobb oldalon hármas számrendszerben).
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3ARuboszamI02" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3ARuboszamI02'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.2.</b><br /> <a name="sz_ii_polinom2_051114_HA_02_kitolto" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Bizonyítsuk be az alábbi számról, hogy nem egész!

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:mfrac><m:mrow><m:mn>8</m:mn><m:mi>&ensp;</m:mi><m:mn>795</m:mn><m:mi>&ensp;</m:mi><m:mn>689</m:mn><m:mo>&middot;</m:mo><m:mn>8</m:mn><m:mi>&ensp;</m:mi><m:mn>795</m:mn><m:mi>&ensp;</m:mi><m:mn>688</m:mn><m:mo>&middot;</m:mo><m:mn>8</m:mn><m:mi>&ensp;</m:mi><m:mn>795</m:mn><m:mi>&ensp;</m:mi><m:mn>687</m:mn><m:mo>&middot;</m:mo><m:mn>8</m:mn><m:mi>&ensp;</m:mi><m:mn>795</m:mn><m:mi>&ensp;</m:mi><m:mn>686</m:mn></m:mrow>

<m:mrow><m:mn>8</m:mn><m:mi>&ensp;</m:mi><m:mn>795</m:mn><m:mi>&ensp;</m:mi>

<m:msup><m:mrow><m:mn>688</m:mn></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>8</m:mn><m:mi>&ensp;</m:mi><m:mn>795</m:mn><m:mi>&ensp;</m:mi>

<m:msup><m:mrow><m:mn>686</m:mn></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>8</m:mn><m:mi>&ensp;</m:mi><m:mn>795</m:mn><m:mi>&ensp;</m:mi>

<m:msup><m:mrow><m:mn>684</m:mn></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>8</m:mn><m:mi>&ensp;</m:mi><m:mn>795</m:mn><m:mi>&ensp;</m:mi>

<m:msup><m:mrow><m:mn>682</m:mn></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

</m:mrow>

</m:mfrac>

</m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Asz_ii_polinom2_051114_HA_02_kitolto" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Asz_ii_polinom2_051114_HA_02_kitolto'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.3.</b><br /> <a name="f_ii_20051017_03_HA" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Messük el az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>y</m:mi><m:mo>=</m:mo>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

</m:mrow></m:math> függvény grafikonját rögzített <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>m</m:mi></m:mrow></m:math>

meredekségű egyenesekkel és vizsgáljuk a metszéspontok közti

szakasz felezőpontjának mértani helyét. Tegyünk megfigyelést,

fogalmazzunk meg állítást ás próbáljuk meg igazolni állításunkat!
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Af_ii_20051017_03_HA" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Af_ii_20051017_03_HA'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.4.</b><br /> <a name="a_ii_20051017_24_HA" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Határozzuk meg

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:mfrac><m:mrow><m:mn>2</m:mn><m:mo>-</m:mo><m:msqrt><m:mrow><m:mn>3</m:mn></m:mrow></m:msqrt></m:mrow>

<m:mrow><m:msqrt><m:mrow><m:mn>2</m:mn></m:mrow></m:msqrt><m:mo>-</m:mo><m:msqrt><m:mrow><m:mn>2</m:mn><m:mo>-</m:mo><m:msqrt><m:mrow><m:mn>3</m:mn></m:mrow></m:msqrt></m:mrow></m:msqrt></m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow><m:mn>2</m:mn><m:mo>+</m:mo><m:msqrt><m:mrow><m:mn>3</m:mn></m:mrow></m:msqrt></m:mrow>

<m:mrow><m:msqrt><m:mrow><m:mn>2</m:mn></m:mrow></m:msqrt><m:mo>+</m:mo><m:msqrt><m:mrow><m:mn>2</m:mn><m:mo>+</m:mo><m:msqrt><m:mrow><m:mn>3</m:mn></m:mrow></m:msqrt></m:mrow></m:msqrt></m:mrow>

</m:mfrac>

<m:mo>-</m:mo><m:msqrt><m:mrow><m:mn>2</m:mn></m:mrow></m:msqrt></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

pontos értékét!
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_20051017_24_HA" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_20051017_24_HA'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.5.</b><br /> <a name="Komal_Gy2822_1993_10_315o" />[<a href="bib_box.php?mode=sne---j-&amp;citation_num=115" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num=115'); return false;">115</a>] Legyen <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>f</m:mi><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo stretchy="false">)</m:mo><m:mo>=</m:mo>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>-</m:mo><m:mi>x</m:mi><m:mo>+</m:mo><m:mn>1</m:mn></m:mrow></m:math>. Bizonyítsuk be, hogy minden <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>m</m:mi><m:mo>&gt;</m:mo><m:mn>1</m:mn></m:mrow></m:math>

egész esetén <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>m</m:mi></m:mrow></m:math>, <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>f</m:mi><m:mo stretchy="false">(</m:mo><m:mi>m</m:mi><m:mo stretchy="false">)</m:mo></m:mrow></m:math>, <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>f</m:mi><m:mrow><m:mo> </m:mo><m:mo>(</m:mo></m:mrow><m:mi>f</m:mi><m:mo stretchy="false">(</m:mo><m:mi>m</m:mi><m:mo stretchy="false">)</m:mo><m:mrow><m:mo> </m:mo><m:mo>)</m:mo></m:mrow></m:mrow></m:math>, <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>f</m:mi><m:mrow><m:mo> </m:mo><m:mo>(</m:mo></m:mrow><m:mi>f</m:mi><m:mrow><m:mo> </m:mo><m:mo>(</m:mo></m:mrow><m:mi>f</m:mi><m:mo stretchy="false">(</m:mo><m:mi>m</m:mi><m:mo stretchy="false">)</m:mo><m:mrow><m:mo> </m:mo><m:mo>)</m:mo></m:mrow><m:mrow><m:mo> </m:mo><m:mo>)</m:mo></m:mrow></m:mrow></m:math>, <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mo>&#x2026;</m:mo></m:mrow></m:math> páronként relatív prímek.
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy2822_1993_10_315o" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy2822_1993_10_315o'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.6.</b><br /> <a name="Komal_Gy2182_1984_11_388o" />[<a href="bib_box.php?mode=sne---j-&amp;citation_num=115" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num=115'); return false;">115</a>] Bontsuk fel az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>f</m:mi><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo stretchy="false">)</m:mo><m:mo>=</m:mo><m:mn>2</m:mn>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>5</m:mn><m:mi>x</m:mi><m:mo>-</m:mo><m:mn>3</m:mn></m:mrow></m:math> függvényt két szigorúan monoton

függvény különbségére!
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy2182_1984_11_388o" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy2182_1984_11_388o'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.7.</b><br /> <a name="Komal_Gy2904_1995_1_13o" />[<a href="bib_box.php?mode=sne---j-&amp;citation_num=115" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num=115'); return false;">115</a>] Az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>a</m:mi></m:mrow></m:math>, <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>b</m:mi></m:mrow></m:math> paraméterek mely értékei esetén lesz az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mo stretchy="false">&verbar;</m:mo>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mi mathvariant="italic">ax</m:mi><m:mo>+</m:mo><m:mi>b</m:mi><m:mo stretchy="false">&verbar;</m:mo></m:mrow></m:math>

függvénynek a <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mrow><m:mo>[</m:mo><m:mo>-</m:mo><m:mn>1</m:mn><m:mo>;</m:mo><m:mn>1</m:mn><m:mo>]</m:mo></m:mrow></m:mrow></m:math> intervallumon vett maximuma

minimális?
<br />&nbsp;<br /></div>

<div class="feladat"><b>Feladat: 5.8.</b><br /> <a name="Komal_Gy3049_1996_12_522o" />[<a href="bib_box.php?mode=sne---j-&amp;citation_num=115" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num=115'); return false;">115</a>] Az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msub><m:mrow><m:mi>f</m:mi></m:mrow><m:mrow><m:mn>1</m:mn></m:mrow>

</m:msub>

<m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo stretchy="false">)</m:mo><m:mo>=</m:mo>

<m:msub><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>1</m:mn></m:mrow>

</m:msub>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msub><m:mrow><m:mi>b</m:mi></m:mrow><m:mrow><m:mn>1</m:mn></m:mrow>

</m:msub>

<m:mi>x</m:mi><m:mo>+</m:mo>

<m:msub><m:mrow><m:mi>c</m:mi></m:mrow><m:mrow><m:mn>1</m:mn></m:mrow>

</m:msub>

</m:mrow></m:math>,  <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msub><m:mrow><m:mi>f</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msub>

<m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo stretchy="false">)</m:mo><m:mo>=</m:mo>

<m:msub><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msub>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msub><m:mrow><m:mi>b</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msub>

<m:mi>x</m:mi><m:mo>+</m:mo>

<m:msub><m:mrow><m:mi>c</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msub>

</m:mrow></m:math> függvények

grafikonjainak nincs közös pontja és főegyütthatóik szorzata

negatív (<m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msub><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>1</m:mn></m:mrow>

</m:msub>

<m:mo>&middot;</m:mo>

<m:msub><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msub>

<m:mo>&lt;</m:mo><m:mn>0</m:mn></m:mrow></m:math>). Bizonyítsuk be, hogy van olyan

egyenes, amellyel grafikonjaik elválaszthatók!
<br />&nbsp;<br /></div>

<div class="feladat"><b>Feladat: 5.9.</b><br /> <a name="a_ii_20051017_17_HA" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Döntsük el, hogy 

<m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mroot><m:mrow><m:mn>2</m:mn><m:mo>+</m:mo><m:msqrt><m:mrow><m:mn>5</m:mn></m:mrow></m:msqrt></m:mrow><m:mrow><m:mn>3</m:mn></m:mrow></m:mroot><m:mo>+</m:mo><m:mroot><m:mrow><m:mn>2</m:mn><m:mo>-</m:mo><m:msqrt><m:mrow><m:mn>5</m:mn></m:mrow></m:msqrt></m:mrow><m:mrow><m:mn>3</m:mn></m:mrow></m:mroot></m:mrow></m:math>

racionális vagy irracionális!
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3Aa_ii_20051017_17_HA" target="_blank" onclick="mutat('exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3Aa_ii_20051017_17_HA'); return false;">&nbsp;Segítség, útmutatás&nbsp;</a>&nbsp;] , [ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_20051017_17_HA" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_20051017_17_HA'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.10.</b><br /> <a name="vegyes_ii_20051017_01_HA" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>A valós számok halmazában értelmezett <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mo>&SmallCircle;</m:mo></m:mrow></m:math>  műveletre (amelynél

<m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>x</m:mi><m:mo>,</m:mo><m:mi>y</m:mi><m:mo>&isin;</m:mo><m:mi>R</m:mi></m:mrow></m:math> esetén <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>&SmallCircle;</m:mo><m:mi>y</m:mi><m:mo stretchy="false">)</m:mo><m:mo>&isin;</m:mo><m:mi>R</m:mi></m:mrow></m:math>) minden <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>x</m:mi><m:mo>,</m:mo><m:mi>y</m:mi><m:mo>,</m:mo><m:mi>z</m:mi></m:mrow></m:math> valós szám esetén teljesülnek a következő tulajdonságok:

<div class="p"><!----></div>

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mi>x</m:mi><m:mo>&SmallCircle;</m:mo><m:mi>y</m:mi><m:mo>=</m:mo><m:mi>y</m:mi><m:mo>&SmallCircle;</m:mo><m:mi>x</m:mi><m:mo>,</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

 <br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>&SmallCircle;</m:mo><m:mi>y</m:mi><m:mo stretchy="false">)</m:mo><m:mo>&middot;</m:mo><m:mi>z</m:mi><m:mo>=</m:mo><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>&middot;</m:mo><m:mi>z</m:mi><m:mo stretchy="false">)</m:mo><m:mo>&SmallCircle;</m:mo><m:mo stretchy="false">(</m:mo><m:mi>y</m:mi><m:mo>&middot;</m:mo><m:mi>z</m:mi><m:mo stretchy="false">)</m:mo><m:mo>,</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>&SmallCircle;</m:mo><m:mi>y</m:mi><m:mo stretchy="false">)</m:mo><m:mo>+</m:mo><m:mi>z</m:mi><m:mo>=</m:mo><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>+</m:mo><m:mi>z</m:mi><m:mo stretchy="false">)</m:mo><m:mo>&SmallCircle;</m:mo><m:mo stretchy="false">(</m:mo><m:mi>y</m:mi><m:mo>+</m:mo><m:mi>z</m:mi><m:mo stretchy="false">)</m:mo><m:mo>.</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

 Mennyi <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>1999</m:mn><m:mo>&SmallCircle;</m:mo><m:mn>2000</m:mn></m:mrow></m:math>?
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Avegyes_ii_20051017_01_HA" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Avegyes_ii_20051017_01_HA'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.11.</b><br /> <a name="vegyes_ii_20051017_02_HA" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Bizonyítsuk be, hogy ha az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>3</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi mathvariant="italic">ax</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mi mathvariant="italic">bx</m:mi><m:mo>+</m:mo><m:mi>c</m:mi><m:mo>=</m:mo><m:mn>0</m:mn></m:mrow></m:math>  egyenlet

összes gyöke valós szám, akkor <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msup><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>&ge;</m:mo><m:mn>3</m:mn><m:mi>b</m:mi></m:mrow></m:math> (<m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>a</m:mi><m:mo>,</m:mo><m:mi>b</m:mi><m:mo>,</m:mo><m:mi>c</m:mi></m:mrow></m:math> adott valós

számok)!
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Avegyes_ii_20051017_02_HA" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Avegyes_ii_20051017_02_HA'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.12.</b><br /> <a name="vegyes_ii_20051017_03_HA" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Oldjuk meg a pozitív prímszámok halmazán a következő egyenletet:

<m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>3</m:mn>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>6</m:mn><m:mi>x</m:mi><m:mo>=</m:mo><m:mn>2</m:mn>

<m:msup><m:mrow><m:mi>y</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>7</m:mn><m:mi>y</m:mi><m:mo>.</m:mo></m:mrow></m:math>
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Avegyes_ii_20051017_03_HA" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Avegyes_ii_20051017_03_HA'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.13.</b><br /> <a name="vegyes_ii_20051017_04_HA" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Igazoljuk, hogy ha <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>a</m:mi><m:mo>,</m:mo><m:mi>b</m:mi><m:mo>,</m:mo><m:mi>n</m:mi></m:mrow></m:math> olyan természetes számok, melyekre

<m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msup><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow>

<m:msup><m:mrow><m:mn>2</m:mn></m:mrow><m:mrow><m:mi>n</m:mi></m:mrow>

</m:msup>

</m:mrow>

</m:msup>

<m:mo>-</m:mo>

<m:msup><m:mrow><m:mi>b</m:mi></m:mrow><m:mrow>

<m:msup><m:mrow><m:mn>2</m:mn></m:mrow><m:mrow><m:mi>n</m:mi></m:mrow>

</m:msup>

</m:mrow>

</m:msup>

</m:mrow></m:math> osztható 9-cel, akkor <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msup><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>-</m:mo>

<m:msup><m:mrow><m:mi>b</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

</m:mrow></m:math> is osztható

9-cel!
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Avegyes_ii_20051017_04_HA" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Avegyes_ii_20051017_04_HA'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.14.</b><br /> <a name="sz_ii_polinom2_051114_HA_01_kitolto" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi mathvariant="italic">ABC</m:mi></m:mrow></m:math> háromszög oldalai között az alábbi összefüggés áll fenn:

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mo stretchy="false">(</m:mo>

<m:msup><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>b</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>c</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:msup><m:mrow><m:mo stretchy="false">)</m:mo></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>=</m:mo><m:mn>4</m:mn>

<m:msup><m:mrow><m:mi>b</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo stretchy="false">(</m:mo>

<m:msup><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>c</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo stretchy="false">)</m:mo><m:mo>+</m:mo><m:mn>3</m:mn>

<m:msup><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:msup><m:mrow><m:mi>c</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>.</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

Mekkora a <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi mathvariant="italic">&beta;</m:mi></m:mrow></m:math> szög?
<br />&nbsp;<br /></div>

<div class="feladat"><b>Feladat: 5.15.</b><br /> <a name="Kurschak_1918_3" />[<a href="bib_box.php?mode=sne---j-&amp;citation_num=121" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num=121'); return false;">121</a>] Tegyük fel, hogy az

<table width="100%"><tr><td align="center"><br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:msup><m:mrow><m:mi mathvariant="italic">ax</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>2</m:mn><m:mi mathvariant="italic">bx</m:mi><m:mo>+</m:mo><m:mi>c</m:mi><m:mo>&ge;</m:mo><m:mn>0</m:mn><m:mo>,</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

<a name="eq:Kurschak_1918_3_a" /></td><td width="1">(1)</td></tr></table>

<div class="p"><!----></div>

<table width="100%"><tr><td align="center"><br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:msup><m:mrow><m:mi mathvariant="italic">px</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>2</m:mn><m:mi mathvariant="italic">qx</m:mi><m:mo>+</m:mo><m:mi>r</m:mi><m:mo>&ge;</m:mo><m:mn>0</m:mn></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

<a name="eq:Kurschak_1918_3_b" /></td><td width="1">(2)</td></tr></table>

<div class="p"><!----></div>

egyenlőtlenségek minden <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>x</m:mi></m:mrow></m:math> valós szám esetén teljesülnek.

Mutassuk meg, hogy ekkor az

<table width="100%"><tr><td align="center"><br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:msup><m:mrow><m:mi mathvariant="italic">apx</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>2</m:mn><m:mi mathvariant="italic">bqx</m:mi><m:mo>+</m:mo><m:mi mathvariant="italic">cr</m:mi><m:mo>&ge;</m:mo><m:mn>0</m:mn></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

<a name="eq:Kurschak_1918_3_c" /></td><td width="1">(3)</td></tr></table>

<div class="p"><!----></div>

egyenlőtlenség is teljesül minden valós <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>x</m:mi></m:mrow></m:math> esetén!
<br />&nbsp;<br /></div>

<div class="feladat"><b>Feladat: 5.16.</b><br /> <a name="Komal_Gy_2423_1988_2_73" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Legyen <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>f</m:mi><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo stretchy="false">)</m:mo><m:mo>=</m:mo>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>-</m:mo><m:mn>6</m:mn><m:mi>x</m:mi><m:mo>+</m:mo><m:mn>5</m:mn></m:mrow></m:math>. Ábrázoljuk derékszögű

koordinátarendszerben azokat a <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>P</m:mi><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>;</m:mo><m:mi>y</m:mi><m:mo stretchy="false">)</m:mo></m:mrow></m:math> pontokat, amelyeknek <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>;</m:mo><m:mi>y</m:mi><m:mo stretchy="false">)</m:mo></m:mrow></m:math> koordinátáira <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>f</m:mi><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo stretchy="false">)</m:mo><m:mo>&ge;</m:mo><m:mi>f</m:mi><m:mo stretchy="false">(</m:mo><m:mi>y</m:mi><m:mo stretchy="false">)</m:mo></m:mrow></m:math>.
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3AKomal_Gy_2423_1988_2_73" target="_blank" onclick="mutat('exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3AKomal_Gy_2423_1988_2_73'); return false;">&nbsp;Segítség, útmutatás&nbsp;</a>&nbsp;] , [ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy_2423_1988_2_73" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy_2423_1988_2_73'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.17.</b><br /> <a name="Komal_Gy_2424_1988_1_28" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Határozzuk meg minden pozitív egész <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>n</m:mi></m:mrow></m:math>-re az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:msqrt><m:mrow>

<m:msup><m:mrow><m:mi>n</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mi>n</m:mi><m:mo>+</m:mo><m:mn>1</m:mn></m:mrow></m:msqrt></m:mrow></m:math> számban a tizedesvessző után álló első számjegyet!
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3AKomal_Gy_2424_1988_1_28" target="_blank" onclick="mutat('exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3AKomal_Gy_2424_1988_1_28'); return false;">&nbsp;Segítség, útmutatás&nbsp;</a>&nbsp;] , [ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy_2424_1988_1_28" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy_2424_1988_1_28'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.18.</b><br /> <a name="harmadfokujatek_2005_11_10_HA_10" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>A táblára az alábbi félkész egyenletet írták:

<table width="100%"><tr><td align="center"><br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>3</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mi>&emsp;&emsp;&emsp;&emsp;&emsp;&emsp;</m:mi><m:mi>x</m:mi><m:mo>+</m:mo><m:mi>&emsp;&emsp;&emsp;&emsp;&emsp;&emsp;</m:mi><m:mo>=</m:mo><m:mn>0</m:mn></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

<a name="eq:harmadfokujatek_2005_11_10_HA_10" /></td><td width="1">(1)</td></tr></table>

<div class="p"><!----></div>

Ketten játszanak. Kezdő a három üres téglalap egyikébe alkalmas

egész számot írhat. Ezután Második a megmaradt két téglalap

egyikébe tetszőleges egész számot ír, végül Kezdő az utolsó üresen

maradt téglalapba ismét egy alkalmas egész számot ír.

<div class="p"><!----></div>

Kezdő akkor nyer, ha a kitöltés után kapott hatmadfokú egyenletnek

van három - nem feltétlenül különböző - valós gyöke. Egyébként

Második nyer. Kinek van nyerő stratégiája?
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aharmadfokujatek_2005_11_10_HA_10" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aharmadfokujatek_2005_11_10_HA_10'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.19.</b><br /> <a name="Komal_Gy_2439_1988_4_166_AD_1987" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Melyek azok az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>x</m:mi></m:mrow></m:math>, <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>y</m:mi></m:mrow></m:math>, <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>z</m:mi></m:mrow></m:math> valós számok, amelyekre

<table width="100%"><tr><td align="center"><br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:mfrac><m:mrow>

<m:msup><m:mrow><m:mi>y</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>z</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>-</m:mo>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

</m:mrow>

<m:mrow><m:mn>2</m:mn><m:mi mathvariant="italic">yz</m:mi></m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow>

<m:msup><m:mrow><m:mi>z</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>-</m:mo>

<m:msup><m:mrow><m:mi>y</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

</m:mrow>

<m:mrow><m:mn>2</m:mn><m:mi mathvariant="italic">zx</m:mi></m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>y</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>-</m:mo>

<m:msup><m:mrow><m:mi>z</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

</m:mrow>

<m:mrow><m:mn>2</m:mn><m:mi mathvariant="italic">xy</m:mi></m:mrow>

</m:mfrac>

<m:mo>=</m:mo><m:mn>1</m:mn><m:mo>?</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

<a name="eq:Komal_F_2528_1985_11_378" /></td><td width="1">(1)</td></tr></table>

<div class="p"><!----></div>
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3AKomal_Gy_2439_1988_4_166_AD_1987" target="_blank" onclick="mutat('exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3AKomal_Gy_2439_1988_4_166_AD_1987'); return false;">&nbsp;Segítség, útmutatás&nbsp;</a>&nbsp;] , [ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy_2439_1988_4_166_AD_1987" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy_2439_1988_4_166_AD_1987'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.20.</b><br /> <a name="Komal_F_2528_1985_11_378" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Egy háromszög körülírt és beírt körének sugara <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>170</m:mn></m:mrow></m:math> ill. <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>12</m:mn></m:mrow></m:math> egység,

a háromszög kerülete <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>416</m:mn></m:mrow></m:math> egység. Mekkorák a szögei?
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3AKomal_F_2528_1985_11_378" target="_blank" onclick="mutat('exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3AKomal_F_2528_1985_11_378'); return false;">&nbsp;Segítség, útmutatás&nbsp;</a>&nbsp;] , [ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_F_2528_1985_11_378" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_F_2528_1985_11_378'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.21.</b><br /> <a name="a_ii_polinom02_051111_HA_30" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Oldjuk meg a következő egyenletrendszert:

<table width="100%"><tr><td align="center">

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mrow><m:mo> </m:mo>

<m:mtable>

<m:mtr><m:mtd columnalign="right"><m:mrow><m:mroot><m:mrow><m:mi>x</m:mi><m:mo>-</m:mo><m:mn>3</m:mn></m:mrow><m:mrow><m:mn>3</m:mn></m:mrow></m:mroot><m:mo>+</m:mo><m:mroot><m:mrow><m:mi>y</m:mi><m:mo>+</m:mo><m:mn>4</m:mn></m:mrow><m:mrow><m:mn>3</m:mn></m:mrow></m:mroot></m:mrow></m:mtd><m:mtd columnalign="left"><m:mrow><m:mo>=</m:mo><m:mn>11</m:mn></m:mrow></m:mtd></m:mtr>

<m:mtr><m:mtd columnalign="right"><m:mrow><m:mi>x</m:mi><m:mo>+</m:mo><m:mi>y</m:mi></m:mrow></m:mtd><m:mtd columnalign="left"><m:mrow><m:mo>=</m:mo><m:mn>340</m:mn></m:mrow></m:mtd></m:mtr></m:mtable>

<m:mo>}</m:mo></m:mrow></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

<a name="eq:a_ii_polinom02_051111_HA_30" /></td><td width="1">(1)</td></tr></table>

<div class="p"><!----></div>
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_polinom02_051111_HA_30" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_polinom02_051111_HA_30'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.22.</b><br /> <a name="a_ii_polinom02_051111_HA_31" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Oldjuk meg a következő egyenletrendszert:

<table width="100%"><tr><td align="center"><br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mrow><m:mo> </m:mo>

<m:mtable>

<m:mtr><m:mtd columnalign="right"><m:mrow>

<m:mfrac><m:mrow><m:mn>1</m:mn></m:mrow>

<m:mrow><m:mn>2</m:mn><m:mo>-</m:mo><m:mi>x</m:mi><m:mo>+</m:mo><m:mn>2</m:mn><m:mi>y</m:mi></m:mrow>

</m:mfrac>

<m:mo>-</m:mo>

<m:mfrac><m:mrow><m:mn>1</m:mn></m:mrow>

<m:mrow><m:mi>x</m:mi><m:mo>+</m:mo><m:mn>2</m:mn><m:mi>y</m:mi><m:mo>-</m:mo><m:mn>1</m:mn></m:mrow>

</m:mfrac>

</m:mrow></m:mtd><m:mtd columnalign="left"><m:mrow><m:mo>=</m:mo><m:mn>2</m:mn></m:mrow></m:mtd></m:mtr>

<m:mtr><m:mtd columnalign="right"><m:mrow>

<m:mfrac><m:mrow><m:mn>1</m:mn></m:mrow>

<m:mrow><m:mn>2</m:mn><m:mo>-</m:mo><m:mi>x</m:mi><m:mo>+</m:mo><m:mn>2</m:mn><m:mi>y</m:mi></m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow><m:mn>1</m:mn></m:mrow>

<m:mrow><m:mi>x</m:mi><m:mo>+</m:mo><m:mn>2</m:mn><m:mi>y</m:mi><m:mo>-</m:mo><m:mn>1</m:mn></m:mrow>

</m:mfrac>

</m:mrow></m:mtd><m:mtd columnalign="left"><m:mrow><m:mo>=</m:mo><m:mn>4</m:mn></m:mrow></m:mtd></m:mtr></m:mtable>

<m:mo>}</m:mo></m:mrow></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

<a name="eq:a_ii_polinom02_051111_HA_30" /></td><td width="1">(1)</td></tr></table>

<div class="p"><!----></div>
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_polinom02_051111_HA_31" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_polinom02_051111_HA_31'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.23.</b><br /> <a name="a_ii_polinom02_051111_HA_39" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Határozzuk meg az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>-</m:mo><m:mn>5</m:mn>

<m:msup><m:mrow><m:mo stretchy="false">)</m:mo></m:mrow><m:mrow><m:mn>4</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo>-</m:mo><m:mn>4</m:mn>

<m:msup><m:mrow><m:mo stretchy="false">)</m:mo></m:mrow><m:mrow><m:mn>4</m:mn></m:mrow>

</m:msup>

<m:mo>=</m:mo><m:mn>97</m:mn></m:mrow></m:math> egyenlet valós

gyökeit!<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_polinom02_051111_HA_39" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_polinom02_051111_HA_39'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.24.</b><br /> <a name="Komal_Gy2247_1985_11_390" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Határozzuk meg az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi mathvariant="italic">xy</m:mi></m:mrow></m:math> szorzat értékét, ha <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>x</m:mi></m:mrow></m:math> és <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>y</m:mi></m:mrow></m:math> olyan

egymástól különböző valós számok, amelyekre

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:mfrac><m:mrow><m:mn>1</m:mn></m:mrow>

<m:mrow><m:mn>1</m:mn><m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

</m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow><m:mn>1</m:mn></m:mrow>

<m:mrow><m:mn>1</m:mn><m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>y</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

</m:mrow>

</m:mfrac>

<m:mo>=</m:mo>

<m:mfrac><m:mrow><m:mn>2</m:mn></m:mrow>

<m:mrow><m:mn>1</m:mn><m:mo>+</m:mo><m:mi mathvariant="italic">xy</m:mi></m:mrow>

</m:mfrac>

<m:mo>.</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy2247_1985_11_390" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3AKomal_Gy2247_1985_11_390'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.25.</b><br /> <a name="a_i_hatv_szamprimfvegy_haft_02" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>A <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>10</m:mn></m:mrow></m:math> mely pozitív egész kitevős hatványai írhatók fel két

pozitív négyzetszám összegeként?
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_hatv_szamprimfvegy_haft_02" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_hatv_szamprimfvegy_haft_02'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.26.</b><br /> <a name="a_i_hatv_szamprimfvegy_haft_03" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Hány megoldása van a pozitív egészek körében az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msup><m:mrow><m:mi>a</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>b</m:mi></m:mrow><m:mrow><m:mn>3</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo>

<m:msup><m:mrow><m:mi>c</m:mi></m:mrow><m:mrow><m:mn>4</m:mn></m:mrow>

</m:msup>

<m:mo>=</m:mo>

<m:msup><m:mrow><m:mi>d</m:mi></m:mrow><m:mrow><m:mn>5</m:mn></m:mrow>

</m:msup>

</m:mrow></m:math> egyenletnek?
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_hatv_szamprimfvegy_haft_03" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_hatv_szamprimfvegy_haft_03'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.27.</b><br /> <a name="a_ii_hatv_mertani_haft_02" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Egy bolha ugrál a síkon. A koordinátarendszer origójából indul,

első ugrásával <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mo stretchy="false">(</m:mo><m:mn>1</m:mn><m:mo>;</m:mo><m:mn>0</m:mn><m:mo stretchy="false">)</m:mo></m:mrow></m:math>-ba érkezik. Minden további ugrása

feleakkora, mint a megelőző volt. Hová jut 48. ugrásával a bolha,

ha minden ugrása után <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msup><m:mrow><m:mn>90</m:mn></m:mrow><m:mrow><m:mo>&SmallCircle;</m:mo></m:mrow>

</m:msup>

</m:mrow></m:math>-kal elfordul (lásd az <a href="#fig:a_ii_hatv_mertani_haft_02_fela" target="_self">1</a>. ábrát)

<div class="p"><!----></div>

<b>a)</b> mindig ugyanabban a forgásirányban?

<div class="p"><!----></div>

<b>b)</b> váltakozó irányban?

<div class="p"><!----></div>

<a name="fig:a_ii_hatv_mertani_haft_02_fela" /><div align="center"><img src="/cache/figures/chs_a_ii/a_ii_hatv_mertani_haft_02_fela.png" /><br />1. ábra</div>

<div class="p"><!----></div>
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_hatv_mertani_haft_02" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_ii_hatv_mertani_haft_02'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.28.</b><br /> <a name="a_i_babaisuranyi_HP_20100906_01" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Tizes számrendszerben <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>12</m:mn><m:mo>=</m:mo><m:mn>3</m:mn><m:mo>&times;</m:mo><m:mn>4</m:mn></m:mrow></m:math>, hatosban pedig <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>3</m:mn><m:mo>&times;</m:mo><m:mn>2</m:mn><m:mo>=</m:mo><m:mn>10</m:mn></m:mrow></m:math>. Határozzuk meg az összes olyan számrendszert és számot, amely két egymás utáni számjegyből áll és a két következő szám szorzataként álljon elő. (Csökkenő vagy emelkedő sorrendben, mint a példákban.)
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_babaisuranyi_HP_20100906_01" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_babaisuranyi_HP_20100906_01'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.29.</b><br /> <a name="a_i_molnar3_HP_20100906_01" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Határozzuk meg az alábbi egyenlet megoldásait:

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:msqrt><m:mrow><m:mi>x</m:mi><m:mo>+</m:mo><m:msqrt><m:mrow><m:mn>2</m:mn><m:mi>x</m:mi><m:mo>-</m:mo><m:mn>1</m:mn></m:mrow></m:msqrt></m:mrow></m:msqrt><m:mo>+</m:mo><m:msqrt><m:mrow><m:mi>x</m:mi><m:mo>-</m:mo><m:msqrt><m:mrow><m:mn>2</m:mn><m:mi>x</m:mi><m:mo>-</m:mo><m:mn>1</m:mn></m:mrow></m:msqrt></m:mrow></m:msqrt><m:mo>=</m:mo><m:mn>2</m:mn><m:mo>.</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3Aa_i_molnar3_HP_20100906_01" target="_blank" onclick="mutat('exercise_box.php?mode=sneh--j-&amp;label=A.II%3A%3Aa_i_molnar3_HP_20100906_01'); return false;">&nbsp;Segítség, útmutatás&nbsp;</a>&nbsp;] , [ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar3_HP_20100906_01" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar3_HP_20100906_01'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.30.</b><br /> <a name="a_i_molnar15_HP_20100906_02" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Állapítsuk meg két szám negyedik hatványainak öszegét, ha a számok összege 10, szorzatuk 4.
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar15_HP_20100906_02" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar15_HP_20100906_02'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.31.</b><br /> <a name="a_i_molnar16_HP_20100906_03" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Megoldandó a következő egyenletrendszer

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow>

<m:mtable>

<m:mtr><m:mtd columnalign="right"><m:mrow><m:mi>x</m:mi><m:mo>+</m:mo><m:mi>y</m:mi><m:mo>+</m:mo><m:mi mathvariant="italic">xy</m:mi><m:mo>+</m:mo><m:mn>5</m:mn></m:mrow></m:mtd><m:mtd columnalign="center"><m:mrow><m:mo>=</m:mo></m:mrow></m:mtd><m:mtd columnalign="left"><m:mrow><m:mn>0</m:mn></m:mrow></m:mtd></m:mtr>

<m:mtr><m:mtd columnalign="right"><m:mrow>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mi>y</m:mi><m:mo>+</m:mo>

<m:msup><m:mrow><m:mi mathvariant="italic">xy</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>6</m:mn></m:mrow></m:mtd><m:mtd columnalign="center"><m:mrow><m:mo>=</m:mo></m:mrow></m:mtd><m:mtd columnalign="left"><m:mrow><m:mn>0</m:mn><m:mo>.</m:mo></m:mrow></m:mtd></m:mtr></m:mtable>

</m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar16_HP_20100906_03" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar16_HP_20100906_03'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.32.</b><br /> <a name="a_i_molnar21_HP_20100906_04" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Bizonyítsuk be, hogy ha <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>a</m:mi><m:mo>+</m:mo><m:mi>b</m:mi><m:mo>+</m:mo><m:mi>c</m:mi><m:mo>=</m:mo><m:mn>0</m:mn></m:mrow></m:math>, akkor

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mrow><m:mo>(</m:mo>

<m:mfrac><m:mrow><m:mi>a</m:mi><m:mo>-</m:mo><m:mi>b</m:mi></m:mrow>

<m:mrow><m:mi>c</m:mi></m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow><m:mi>b</m:mi><m:mo>-</m:mo><m:mi>c</m:mi></m:mrow>

<m:mrow><m:mi>a</m:mi></m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow><m:mi>c</m:mi><m:mo>-</m:mo><m:mi>a</m:mi></m:mrow>

<m:mrow><m:mi>b</m:mi></m:mrow>

</m:mfrac>

<m:mo>)</m:mo></m:mrow><m:mrow><m:mo>(</m:mo>

<m:mfrac><m:mrow><m:mi>c</m:mi></m:mrow>

<m:mrow><m:mi>a</m:mi><m:mo>-</m:mo><m:mi>b</m:mi></m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow><m:mi>a</m:mi></m:mrow>

<m:mrow><m:mi>b</m:mi><m:mo>-</m:mo><m:mi>c</m:mi></m:mrow>

</m:mfrac>

<m:mo>+</m:mo>

<m:mfrac><m:mrow><m:mi>b</m:mi></m:mrow>

<m:mrow><m:mi>c</m:mi><m:mo>-</m:mo><m:mi>a</m:mi></m:mrow>

</m:mfrac>

<m:mo>)</m:mo></m:mrow><m:mo>=</m:mo><m:mn>9</m:mn><m:mo>.</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar21_HP_20100906_04" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar21_HP_20100906_04'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.33.</b><br /> <a name="a_i_molnar23_HP_20100906_05" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Legyenek <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi mathvariant="italic">&alpha;</m:mi><m:mo>,</m:mo><m:mi>&ensp;</m:mi><m:mi mathvariant="italic">&beta;</m:mi></m:mrow></m:math> az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mi mathvariant="italic">px</m:mi><m:mo>+</m:mo><m:mn>1</m:mn><m:mo>=</m:mo><m:mn>0</m:mn></m:mrow></m:math> egyenlet gyökei és <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi mathvariant="italic">&gamma;</m:mi><m:mo>,</m:mo><m:mi>&ensp;</m:mi><m:mi mathvariant="italic">&delta;</m:mi></m:mrow></m:math> az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mi mathvariant="italic">qx</m:mi><m:mo>+</m:mo><m:mn>1</m:mn><m:mo>=</m:mo><m:mn>0</m:mn></m:mrow></m:math> egyenlet gyökei. Bizonyítsuk be, hogy

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mo stretchy="false">(</m:mo><m:mi mathvariant="italic">&alpha;</m:mi><m:mo>-</m:mo><m:mi mathvariant="italic">&gamma;</m:mi><m:mo stretchy="false">)</m:mo><m:mo stretchy="false">(</m:mo><m:mi mathvariant="italic">&beta;</m:mi><m:mo>-</m:mo><m:mi mathvariant="italic">&gamma;</m:mi><m:mo stretchy="false">)</m:mo><m:mo stretchy="false">(</m:mo><m:mi mathvariant="italic">&alpha;</m:mi><m:mo>+</m:mo><m:mi mathvariant="italic">&delta;</m:mi><m:mo stretchy="false">)</m:mo><m:mo stretchy="false">(</m:mo><m:mi mathvariant="italic">&beta;</m:mi><m:mo>+</m:mo><m:mi mathvariant="italic">&delta;</m:mi><m:mo stretchy="false">)</m:mo><m:mo>=</m:mo>

<m:msup><m:mrow><m:mi>q</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>-</m:mo>

<m:msup><m:mrow><m:mi>p</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>.</m:mo></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar23_HP_20100906_05" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar23_HP_20100906_05'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>

<div class="feladat"><b>Feladat: 5.34.</b><br /> <a name="a_i_molnar24_HP_20100906_06" /><a href="bib_box.php?mode=sne---j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne---j-&amp;citation_num='); return false;"></a>Határozzuk meg a <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>b</m:mi></m:mrow></m:math> együtthatót a

<br />

<table width="100%"><tr><td align="center">

    <m:math xmlns="http://www.w3.org/1998/Math/MathML">

    <m:mstyle displaystyle="true"><m:mrow><m:mn>4</m:mn>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>4</m:mn></m:mrow>

</m:msup>

<m:mo>-</m:mo><m:mn>11</m:mn>

<m:msup><m:mrow><m:mi>x</m:mi></m:mrow><m:mrow><m:mn>2</m:mn></m:mrow>

</m:msup>

<m:mo>+</m:mo><m:mn>9</m:mn><m:mi>x</m:mi><m:mo>+</m:mo><m:mi>b</m:mi><m:mo>=</m:mo><m:mn>0</m:mn></m:mrow>

    </m:mstyle></m:math>

</td></tr></table>

<br />

egyenletben úgy, hogy legyen az egyenletnek két különböző gyöke, amelyek összege <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mo>-</m:mo><m:mn>1</m:mn></m:mrow></m:math>.
<br />&nbsp;<br /><div align="right">[ <a class="link" href="exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar24_HP_20100906_06" target="_blank" onclick="mutat('exercise_box.php?mode=sne-s-j-&amp;label=A.II%3A%3Aa_i_molnar24_HP_20100906_06'); return false;">&nbsp;Megoldás&nbsp;</a>&nbsp;] </div></div>
<div style="height:30pt;">&nbsp;</div>
<div id="navigation">



<div class="navcenter">
<div class="navdiv">
<a href="index.html">&nbsp;Matkönyv megjelenítő főoldal&nbsp;</a>&nbsp;
|&nbsp;<a href="list_html.php?mode=sne---j-">&nbsp;Matkönyv feladatgyűjtemények listája&nbsp;</a>&nbsp;
|&nbsp;<a href="volume.php?mode=sne---j-&amp;volume=a_ii">&nbsp;Tartalomjegyzék&nbsp;</a></div>
</div></div></body></html>
