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<title>GR.II.4.28</title>
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<b>Feladat: 4.28.</b><br /> <a name="k_ii_091015sl_szimm02" /><a href="bib_box.php?mode=sne-s-j-&amp;citation_num=" target="bib_box" onclick="mutat('bib_box.php?mode=sne-s-j-&amp;citation_num='); return false;"></a> [<a href="bib_box.php?mode=sne-s-j-&amp;citation_num=4" target="bib_box" onclick="window.open('bib_box.php?mode=sne-s-j-&amp;citation_num=4','bib_box','toolbar=no,location=no,directories=no,status=no,menubar=no,width=600,height=150')">4</a>], 14. old.

Mely fák izomorfak a komplementerükkel?
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<a name="_solution_k_ii_091015sl_szimm02" /><b>Megoldás: 4.28</b><br />
Egy <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>n</m:mi></m:mrow></m:math> pontú fában <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>n</m:mi><m:mo>-</m:mo><m:mn>1</m:mn></m:mrow></m:math> él van. Ha izomorf a komplementerével, akkor a komplementerben is ennyi él van, tehát az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>n</m:mi></m:mrow></m:math> pontú teljes gráfban <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mn>2</m:mn><m:mo stretchy="false">(</m:mo><m:mi>n</m:mi><m:mo>-</m:mo><m:mn>1</m:mn><m:mo stretchy="false">)</m:mo></m:mrow></m:math> él van. Másrészt az <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>n</m:mi></m:mrow></m:math> pontú teljes gráf élszáma <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>n</m:mi><m:mo stretchy="false">(</m:mo><m:mi>n</m:mi><m:mo>-</m:mo><m:mn>1</m:mn><m:mo stretchy="false">)</m:mo><m:mo stretchy="false">/</m:mo><m:mn>2</m:mn></m:mrow></m:math>, tehát csak <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>n</m:mi><m:mo>=</m:mo><m:mn>4</m:mn></m:mrow></m:math>-re lehet ilyen fa. <m:math xmlns="http://www.w3.org/1998/Math/MathML">

<m:mrow><m:mi>n</m:mi><m:mo>=</m:mo><m:mn>4</m:mn></m:mrow></m:math> pontú fa a háromágú csillag és a háromélű út. Csak az utóbbi izomorf a komplementerével.
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